India's Rupesh Roy and his Australian partner Stephen Donald defeated the Aussie duo of
Jared Easton and Bernard Tomic to advance to the boys' doubles quarter-finals at the Australian Open, in Melbourne, on Tuesday.
After conceding the first set, sixth seeds Roy and Donald fought back to win the second round match 2-6, 6-3, 6-4.
In the quarter-finals, the Indo-Aussie pair will meet top seeds Roman Jebavy of the Czech Republic and Martin Klizan of Slovakia.
Jebavy and Klizan beat Danila Arsenov and Vladimir Zinyakov of Russia 7-6 (6) 6-4 to reach the last-eight stage.
© Copyright 2007 PTI. All rights reserved. Republication or redistribution of PTI content, including by framing or similar means, is expressly prohibited without the prior written consent.
|
Advertisement
Email this Article 
Print this Article