Rohan Bopanna and Fred Hemmes of The Netherlands stormed into the final of the $50,000 Heineken Challenger, in Ho Chi Minh City, Vietnam, on Firday.

The Indo-Dutch pair defeated Amir Hadad and Andy Ram of Isreal 6-3, 2-6, 6-4 in their semi-fianl match.

They will face the third seeded South African pair of Rik de Voest and Wesley Moodie, who defeated Yen-Hsun Lu of Taiwan and Danai Udomchoke of Thailand 6-7(5), 7-5, 6-4 in the other semi-final.

The duo, who came through by winning the qualifier, demolised Phu-Qui Huynh/Duc-Duong Ngo of Vietnam 6-1, 6-3 in the first round and fourth seed Noam Behr of Isreal and John Hui of Hong Kong 6-3, 3-6, 6-3 in the quarters.

In the singles, Bopanna, who was given a wildcard, lost to top seed Werner Eschauer of Austria 6-7(6), 1-6 in the first round.